7y^2+6y-1=0

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Solution for 7y^2+6y-1=0 equation: 



7y^2+6y-1=0

a = 7; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·7·(-1)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-8}{2*7}=\frac{-14}{14}
=-1
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+8}{2*7}=\frac{2}{14}
=1/7
$

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